Math, asked by shankarbhadani8, 7 months ago

find the amount when p=8000rupee, rate =9% and Time =3 years​

Answers

Answered by sarthakweljali
0

Answer:

ANSWER

Principal for the first year = Rs.8000, Rate = 5% per annum, T = 1 year

Interest for the first year = =

100

P×R×T

=Rs.[

100

8000×5×1

]=Rs.400

∴ Amount at the end of the first year = Rs. (8000 + 400) = Rs. 8400

Now principal for the second year = Rs.8400

Interest for the second year =

100

P×R×T

=Rs.[

100

8400×5×1

]=Rs.420

∴ Amount at the end of the second year = Rs. (8400 + 420) =Rs.8820

Interest for the third year =

100

P×R×T

=Rs.

100

8820×5×1

=Rs.441

∴ Amount at the end of the third year = Rs.(8820 + 441) = Rs. 9261

Now we know that total C.I. = Amount - Principal = Rs. (9261 - 8000) = Rs. 1261

we can also find the C.I. as follows

Total C.I. = Interest for the first year + Interest for the second year + Interest for third year = Rs. (400 + 420 + 441) = Rs.1261

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Answered by Anonymous
0

\color{red}{Principal}

= ₹8000

\color{red}{Rate}

= 9% = 9/100

\color{red}{Time}

= 3 years

\color{red}{Simpleintrest}

= P×R×T

= 8000×(9/100)×3

= ₹2160

\color{red}{Amount}

= P + S.I

= 8000+2160

= ₹10160

\bold{\boxed{GoodNight}}

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