Question

find the and area of an isosceles triangle whose perimeter is 64 cm añd whose base is 24 cm
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Answer 1

Answer:

168.96cm^2

Step-by-step explanation:

let the two equal sides be x each

anothe unequal side = 24cm

perimeter = 64cm

x + x + 24 = 64cm (perimeter is the sum of all sides)

2x + 24 = 64cm

2x = 64-24

2x = 40cm

x =20cm

area of triangle

s =20 +20 + 24

             2

=64/2 = 32

$\sqrt{32(32-20)(32-20)(32-24)$  (using herons formula)

$\sqrt{4*4*2*4*2*4*2*7*2$

2*2*2*2*2*2$\sqrt{7$

64$\sqrt{7$

$\sqrt{7$ =2.64

64*2.64

=168.96cm^2

Answer 2

Answer:

Answer:-

168.96cm^2

Step-by-step explanation:

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