Math, asked by adnan151, 1 year ago

find the angle adc and cad and acd

Attachments:

Answers

Answered by hellypatel53
0
ace=acd+dce=90°
so,
acd+35°=90°
acd=90°-35°
acd=55°
abcd is a cyclic
so,
abc+adc=180°
93°+adc=180°
adc=180°-93°
adc=87°
adc is a triangle
so,
adc+acd+cad=180°
87°+55°+cad=180°
142°+cad=180°
cad=180°-142°
cad=38°

hellypatel53: agr 93 hota to thoda cross me hota
hellypatel53: lamb nhi hota
adnan151: nahi wo sirf rough figure hai
adnan151: aur agar 90° hai to prove karo
hellypatel53: okk
hellypatel53: abcd cyclic h
hellypatel53: is liye abc+adc=180 hoga
hellypatel53: adc=180-93=87
hellypatel53: i edited answer
hellypatel53: and i'm sure the edited answer is right
Similar questions