find the angle adc and cad and acd
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ace=acd+dce=90°
so,
acd+35°=90°
acd=90°-35°
acd=55°
abcd is a cyclic
so,
abc+adc=180°
93°+adc=180°
adc=180°-93°
adc=87°
adc is a triangle
so,
adc+acd+cad=180°
87°+55°+cad=180°
142°+cad=180°
cad=180°-142°
cad=38°
so,
acd+35°=90°
acd=90°-35°
acd=55°
abcd is a cyclic
so,
abc+adc=180°
93°+adc=180°
adc=180°-93°
adc=87°
adc is a triangle
so,
adc+acd+cad=180°
87°+55°+cad=180°
142°+cad=180°
cad=180°-142°
cad=38°
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