find the angle between A=i+j+k. and B=-2i-2j-2k
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a=i+2j-k
b=-i+j-2k
as we know that,for two given vectors a and b,we have:-
a.b=|a|*|b|*cos a^b
where a^b is the angle between the vectors a and b
so, a.b= 1*-1+2*1+-1*2=3
|a|=(1+4+1)^1/2=√6
|b|=(1+1+4)^1/2=√6
from the given equation,we have
3=√6*√6*cos a^b
so,cos a^b=3/6=1/2
so angle between the vectors is 60 degree
b=-i+j-2k
as we know that,for two given vectors a and b,we have:-
a.b=|a|*|b|*cos a^b
where a^b is the angle between the vectors a and b
so, a.b= 1*-1+2*1+-1*2=3
|a|=(1+4+1)^1/2=√6
|b|=(1+1+4)^1/2=√6
from the given equation,we have
3=√6*√6*cos a^b
so,cos a^b=3/6=1/2
so angle between the vectors is 60 degree
Rajalah:
you have copied the question wrong
please check it
I have not copied the question
your vector A and Vector B are wrong
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The answer is in the picture
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u hve copied the ques wrong
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