Question

Find the angle between diagonals of rectangle with perimeter 2p and 3p^2/16

Answer 1

Heya Mate !!!

Here's Your Answer ;-

We are well known with the general thing that the diagonals of a rectangle are always 90°.

So the thing doesn't matter , what the perimeter of the rectangle is , as given ( 2p and 3p^2/16) , the resultant angle of its diagonals will be 90°.

____⭐@dmohit432⭐____

Answer 2

Concept:-

A rectangle is a two-dimensional figure with four sides, four vertices, and four angles. The diagonal of a rectangle is a line segment that connects the two opposite vertices of the rectangle.

Given:-

The perimeter of the rectangle is $2p$ and $3p^2/16$.

Find:-

Find the angle between the diagonals of the rectangle.

Solution:-

First part:

Let us assume that x and y represent the two sides of the rectangular.

We can create two-equation

$x+y = pi\\xy = pi*3/16$

When solving the equations we come up with:

$x = 1/4 \\and\\ y = 3/4$

Second part:

Now we can look at the ratio between them and estimate that if $x/y=3$then the corresponding angles (in the center of the rectangle) will have the same ratio.

Therefore, the angle between the diagonals is either $45, or 135.$