Question

find the angle between given vector a vector= 3i+2j-k and b vector =2i-3j+k

Answer 1

Explanation:

Consider the given vectors ,

a = 3i + 2j - k

b = 2i - 3j + k

Now ,

Use Dot product of vector ,

a . b = ( 3i + 2j - k) . ( 2i - 3j + k )

a . b = 6 - 6 - 1 = -1

$Θ = {cos}^{ - 1} ( - 1) \\ \\ \cos(Θ) \: = - 1 \\ cos(Θ) = \cos(180) \\ \\ Θ = 180$

Thus , the angle between two vectors a and b 180°

Additional concept we use here ,

i . i = 1

j . j = 1

k . k = 1

i . j = 0

i . k = 0

j . k = 0

cos 180° = -1

Answer 2

Answer:

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