Question

find the angle between jcap and kcap?​

Answer 1

Answer:

Let us take dot product of vector i^+j^+k^ with i^.

(i^+j^+k^).i^= 1.= magnitude of ( i^+j^+k^) multiplied by magnitude of i^ multiplied by cosine of angle A between them.

Therefore,

1=[ (1^2+1^2+1^2)^1/2 ](1) cosA.

Therefore,

cosA=1/sqrt(3) OR

A=54.7356 degree.

Answer 2

Answer:

Let us take dot product of vector i^+j^+k^ with i^.

(i^+j^+k^).i^= 1.= magnitude of ( i^+j^+k^) multiplied by magnitude of i^ multiplied by cosine of angle A between them.

Therefore,

1=[ (1^2+1^2+1^2)^1/2 ](1) cosA.

Therefore,

cosA=1/sqrt(3) OR

A=54.7356 degree.