• Find the angle between the following straight lines. 1)y = 4 - 2x, y = 3x + 7 , 2) 3x + 5y = 7, 2x - y +4 = 0 3)y = - 3x + 5, y =1/✓3x -2/✓3 4)ax + by = a + b, a (x - y) + b(x + y) = 2b
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>>Angle between two lines
>>The angle between the lines...
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The angle between the lines 3x+y−7=0 and x+2y+9=0 is
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Correct option is
D
4
π
3x+y−7=0 and x+2y+9=0
write in the form y=mx+c
i.e.y=−3x+7,y=
2
−x
−
2
9
∴m
1
=−3 and m
2
∓−
2
1
tan(A−B)=
∣
∣
∣
∣
∣
1+tanAtanB
tanA−tanB
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
1+(−3)(−y
2
)
−3−(−y
2
)
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
5/2
−5/2
∣
∣
∣
∣
∣
=1
∴ Angle b/w then is tan
−1
(1)=45
∘
=
4
π
Step-by-step explanation:
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