Question

Find the angle between the lines of intersection of the plane x-3y+z=0 and the cone x^2-5y^2+z^2=0.​

Answer 1

Answer:

: The angle between the lines of intersection of the plane x-3y + z = 0 and a quadric cone x^2 - 5y^2 + 2 = 0 is 360⁰