Question

find the angle between the lines x-2y+2=0 and x+3y+4=0​

Answer 1

Step-by-step explanation:

Hope it helps...Uuh...!

Answer 2

The angle between the lines x-2y+2=0 and x+3y+4=0 is equal to π/4.

M1 - the slope of the line x-2y+2 = 0 is equal to 1/2.

M2 - the slope of the line x+3y+4 = 0 is equal to -1/3.

Let the angle between the two lines x-2y+2=0 and x+3y+4=0 be equal to x.

Using the formula tan x = |(M1 - M2)/(1+M1×M2)|

=> tan x = |(1/2 + 1/3)/(1-1/6)|

=> tan x = |(5/6)/(5/6)|

=> tan x = 1

=> x = π/4

The value of the acute angle between the two lines x-2y+2=0 and x+3y+4=0 is equal to π/4.