find the angle between the pl
anes 2x+y+3z-2=0 and x-2y+5=0
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To find the angle between the planes we can find the angle between the normal to the planes.
Normal to the plane 1 is 2i + j + 3k
Normal to plane 2 is i -2j
The angle between 2 can be found by the dot product
(2i+j+3k).(i-2j)= √(4+1+9)√(1+4) cosФ
0 = cosФ
Ф=0°
The angle between the planes is 180° - angle between the normals
= 180°
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