find the angle between the vectors A=6i+8j+10k and B=6i+8j-10k.
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It is very easy to find the angle between two vectors. There are two formulas you can apply one is vector product and other is scalar product.
cos theta = (6×6 + 8×8 - 10×10) / ( 20 )0as we know Cos inverse 0 equals to 90 degree. Therefore this is the angle between these two vectors.
cos theta = (6×6 + 8×8 - 10×10) / ( 20 )0as we know Cos inverse 0 equals to 90 degree. Therefore this is the angle between these two vectors.
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