Question

Find the angle between two equal forces P, when their resultant is equal to (i) P and (ii) P/2.

Answer 1

Step-by-step explanation:

first one is impossible and answer for second one is30°

Answer 2

Answer:(i) 120 degrees (ii) 151.0440

Step-by-step explanation:

here p1=p2=p

$R=\sqrt{P^{2}+P^2+2PP Cos (Teta)}\\P^2={P^2+P^2+2P^2Cos (Teta)} \\P^2=P^2(1+1+2Cos ( Teta)\\1=2+2Cos (Teta)\\1-2=2cos(Tets)\\-1/2=cos (Teta)\\Cos^-1=(Teta)\\(Teta)=120^0$