find the angle between two radii at the centre of the circle given in figure. line PA and PB are tangents to the circle at the other ends of radii and angle APR =130 °. find angle AOB
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angle APR=130
then 180_130=50
then draw a line op,50/2=25
we known that a bisector
makes an angle 90 on the circle so OAP=90 in a triangle sum of angles is 180 so 90+25=115 then 180_115=65
so angle AOB=AOP+POB=65+65=130
then 180_130=50
then draw a line op,50/2=25
we known that a bisector
makes an angle 90 on the circle so OAP=90 in a triangle sum of angles is 180 so 90+25=115 then 180_115=65
so angle AOB=AOP+POB=65+65=130
sohamkolhe:
how APB is 130
they given
no
they give APR = 130
APB=50
how
linear pair
explain full neatly
answer is 130
yes
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