Question

Find the angle between two vectors a=i+j-k b=i-j+k

Answer 1

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A = i + j - k And B = i - j + k

A.B = |A| |B| Cosx

Where X is the angle between these two vectors

A.B = {i.i - j.j - k.k}

A.B = 1 - 1 - 1

A.B = -1

|A| = √3 And |B| = √3

So,

-1 = √3 × √3 Cosx

-1 = 3 Cosx

Cosx = -1/3

x = Cos-¹(-1/3)

So, The angle between vector A and B is Cos-¹(-1/3)

Answer 2

Step-by-step explanation:

i+j-k.i-j+k÷

$\sqrt{1 + 1 + 1 \times \sqrt{1 + 1 + 1} }$

1-1-1÷6=0

cos theta=o