Question

find the angle between x-√3y=5 and x+√3y-7=0​

Answer 1

Answer:

Given equations are,

x-√3y-5 = 0 and x+√3y-7=0

a1 =1, a2 = 1, b1 = -√3, b2 = √3

Using formula,

tan θ = |(a1b2 - b1a2)/(a1a2 + b1b2)|

tan θ = | [1(√3) - (-√3)1] / [1(1) + (-√3)(√3)] |

tan θ = | 2√3 / (-2) | = √3

θ = 60°