find the angle bisector of q. q= 100°
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Answer:
the bisector angle of 100 is its half so it is 50 degree
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Step-by-step explanation:
We know that sum of interior angles of quadrilateral is 360
o
∠P+∠Q+∠R+∠S=360
o
∠P+∠Q+100+50=360
∠P+∠Q=210
o
……………..(1)
OP and OQ are bisectors of angles P and Q,
∠P=2∠OPQ and ∠Q=2∠OQP
So from (i), we have
2∠OPQ+2∠OQP=210
o
2(∠OPQ+∠OQP)=210
o
∠OPQ+∠OQP=105
o
…………….(2)
Consider triangle POQ,
∠POQ+∠OPQ+∠OQP=180
o
∠POQ+105
o
=180
o
[using equation (3)]
∠POQ=180
o
−105
o
∠POQ=75
o
.
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