Question

Find the angle of elevation of the sun when a 7.6-meter flagpole casts a 18.2-meter shadow. Round to the nearest tenth of a degree

Answer 1

$Height \:of \:a \:Flag - pole (AB) = 7.6 \:m$

$Length \:of \:the \: shadow (BC) = 18.2 \:m$

$In \: \triangle ABC ,\: \angle {ABC} = 90\degree$

$tan \:{ACB} = \frac{AB}{BC}$

$\implies tan \:\angle {ACB} = \frac{7.6\:m}{18.2\:m}$

$\implies tan \:\angle {ACB} = 0.417$

$\implies tan \:\angle {ACB} = 0.42$

$\implies tan \:\angle {ACB} = tan 22.8\degree$

$Angle \:of \: Elevation \: \angle {ACB} = 22.8 \degree$

Therefore.,

$\red {Angle \:of \: Elevation\:of \:the \:Sun} \green {= 22.8 \degree}$

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