Question

find the angle of elevation of the top of 15m high tower at a point 15m away from the base of tower

Answer 1

hope this helps you
mark a brainliest

Answer 2

Answer:

45°

Step-by-step explanation:

Refer the attached figure .

Height of tower = AB = 15 m

A point is 15 m away from the base i.e. BC = 15 m

Perpendicular = 15 m

Base = 15 m

We are supposed to find ∠ACB

So, we will use trigonometric ratio:

$Tan\theta = \frac{Perpendicular}{Base}$

$Tan\theta = \frac{15}{15}$

$Tan\theta = 1$

$\theta =tan^{-1}(1)$

$\theta =45^{\circ}$

Thus the angle of elevation of the top of 15m high tower at a point 15m away from the base of tower is 45°