Question

Find the valume of the greatest sphere that can be cut out of the cube of side21 cm . Find the valume of the reamaining piece also

Answer 1

Answer:

the greatest sphere that can be cut from the cube of side 21cm, means the diameter of the sphere will be 21cm.

therefore radius of the sphere=21/2cm  

volume of the sphere=4/3πr³  

=4/3×22/7×21/2×21/2×21/2

=11×21×21  

=4851cm³

hence volume of the sphere is 4851cm³.

given side of the cube=21cm  

volume of the cube=side³

=21³

=9261cm³

volume of the remaining portion of the cube if the sphere has been cut from the cube=9261-4851

                       =4410cm³

Answer 2

Answer:

Volume of the remaining piece = 4410 cm³

Step-by-step explanation:

Given,

  Side of the cube = 21cm

  The greatest sphere will be such that

      Diameter of sphere = side of the cube

     So, the radius of sphere = (side of the cube) /2

                                              r = 21/2 cm

      The volume of the sphere = 4/3 πr³

                                                   = $\frac{4}{3} \frac{22}{7} \frac{21}{2} \frac{21}{2} \frac{21}{2}$

              volume of the sphere = 4851 cm³

                 Volume of the cube = (21x21x21) = 9261 cm³

Volume of the remaining piece = Volume of cube - Volume of the sphere

                                                     = 9261 - 4851

                                                     = 4410 cm³

    Hence,

        Volume of the remaining piece = 4410 cm³

Know more about Sphere:

https://brainly.in/question/29784640?referrer=searchResults

#SPJ3