Question

find the angle of elevation of the top of the tower from the point on the ground which is 3m away from the foot of the tower of height 10√3m

Answer 1

Angle of elevation $\theta$ of top of the tower of height $=10\sqrt3 m$  at a point $3m$  is given as

$\tan\theta=\frac{height}{base}$

$\tan\theta=\frac{10\sqrt3}{3}$

$\tan\theta=\frac{10}{\sqrt3}$

$\theta=80.17^\circ$

Answer 2

hey dear here is your answer


angle of elevation of top of the tower of a height == 10√3 metres



therefore and from point on the ground is 3metres


so tan thetha = 10√3 / 3



hope helps you