Find the angle of projectile for a body to have same horizontal range and maximum height
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Let θ be the angle of projection for which horizontal range and maximum height of a projectile are equal.Now,
H= u sin θ / 2g
R = u sin2θ / g
So, if H=R
then , u sin θ / 2g = u sin2θ / g
or, sin θ / 2 = sin2θ
or, sin θ = 2 (2 sinθ cosθ )
or tan θ = 4
or, θ = tan ( 4)
H= u sin θ / 2g
R = u sin2θ / g
So, if H=R
then , u sin θ / 2g = u sin2θ / g
or, sin θ / 2 = sin2θ
or, sin θ = 2 (2 sinθ cosθ )
or tan θ = 4
or, θ = tan ( 4)
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