find the angle of projectile for which is the horizontal range and the maximum height are equal
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Answer:
R= u 2sin2θ/g
H= u 2 sin 2θ/2g
u 2 sin2θ/2g =u 2sin 2 θ/2g
2sinθcosθ= sin 2 θ/2
ucosθ=sinθ
tanθ=4
θ=tan −1 4
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