Question

Vessel of 1xx10^(-3) m^(3) volume contains an oil. If a pressure of 1.2xx10^(5) N//m^(2) is applied on it , then volume decreases by 0.3xx10(-3) m^(3). The bulk modulus of oil is

Answer 1

Bulk modulus = 171.42 × $10^{6}$ N/m²

Given:

Vessel of $1\times 10^{-3} m^3$ volume contains an oil.

If a pressure of $1.2\times 10^5 N/m^2$ is applied on it.

Volume decreases by $0.3\times 10^{-3} m^3$

To find:

The bulk modulus of oil.

Formula used:

Bulk modulus = $\frac{dp}{dv}$

where       dp = Change in pressure.

                 dv = change in volume.

Explanation:

Pressure of $1.2\times 10^5 N/m^2$ is applied on it.

So dp = Change in pressure. = $1.2\times 10^5 N/m^2$

dv = change in volume.

    = initial volume - final volume

    = $1\times 10^{-3}$ -($0.3\times 10^{-3}$)

    =$0.7\times 10^{-3} m^3$

Bulk modulus = $\frac{dp}{dv}$

Bulk modulus = $\frac{1.2\times 10^5}{0.7\times 10^-^3}$

Bulk modulus = 171.42 × $10^{6}$ N/m²

To learn more...

1)Obtain an expression for bulk modulus. State SI unit and dimensions of 'K'.

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