Physics, asked by priyanshu22231, 1 year ago

find the angle of projection for which are range and H height are equal

Answers

Answered by latajoshi1979
2

Horizontal Range:


(U^2 Sin 2 (A)/g) where 'A' is the projection angle.


Maximum Height:


U^2 [Sin (A)]^2/2 g where 'U' is the projection velocity.


[Sin (A)] ^2 = 2× Sin 2 (A)


Sin (A) = 4 × Cos (A)


tan [A] = 4, A = tan~[4] where '~' is the inverse.


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