Question

Find the angle of projection for which the maximum hieght is equal to one-fourth of horizontal range

Answer 1

Explanation:

hope it would be helpful

Answer 2

Answer:

$\theta = 45 \degree$

Explanation:

We use the relation

$range = \frac{4hmax}{ \tan( \theta) }$

since hmax is one-fourth the horizontal range,

$hmax = \frac{range}{4}$