Question

find the angle of triangle angle A=/5=angle B/4=angle c/3​

Answer 1

Answer:

Given that ∠C=3∠B=2(∠A+∠B)

Solving above equality we get

∠B=2∠A, ∠C=6∠A

But, in a triangle ΔABC we know that ∠A+∠B+∠C=180∘

∴∠A+2∠A+6∠A=180∘

9∠A=180∘

∠A=180∘9

∠A=20∘

∴∠B=2∠A=2(20∘)=40∘

∴∠C=6∠A=6(20∘)=120∘