Find the angle that is one forth of it's supplement
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Answered by
4
Let the angle be a
Supplementary angle = (180 - a)
According to question,
a = (180 - a) /4
=> 4a = 180 - a
=> 5a = 180
=> a = 36
Required angle = 36°
Supplementary angle = (180 - a)
According to question,
a = (180 - a) /4
=> 4a = 180 - a
=> 5a = 180
=> a = 36
Required angle = 36°
Answered by
1
let angles be x.
supplement of x = 180-x.
according to question
x = 180-x/4
4x = 180-x
5x = 180
x = 36°
supplement of x = 180-x.
according to question
x = 180-x/4
4x = 180-x
5x = 180
x = 36°
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