Find the angle, where twice its complement is 100 less than four times its complement. a) 150 b) 100 c) 250 d) 850
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Given,
The twice of the complement of the main angle is 100° less than the four times of it's complement angle.
To find,
The value of the main angle.
Solution,
Let, the main angle = x°
(Assume x as a variable to do the further mathematical calculations.)
Complement of the main angle = (90-x)°
Twice of the complement angle = 2×(90-x) = (180-2x)°
Four times of the complement angle = 4×(90-x) = (360-4x)°
According to the data mentioned in the question,
(360-4x)-100 = 180-2x
360-4x-100 = 180-2x
360-100-180 = 4x-2x
360-280 = 2x
2x = 80
x = 40
Hence, the value of the main angle is 40°.
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