Question

Find the angle , which is double of it's complement and half of it's supplement.​

Answer 1

let the angle be x

Compliment of an angle

is equal to the Difference of it with 90°

And supplement of an angle is the difference of it with 180°

According to the question

then

x=2(90°-x).........(1)

Here (90°-x) is compliment of x

and x=1/2(180°-x) ....(2)

here (180°-x) is supplement of x

putting value of x from (1) in (2)

then

2(90°-x)=1/2(180°-x)

4(90°-x)=(180°-x)

360°-4x=180°-x

360°-180°=-x+4x

180°=3x

x=180°/3

x=60°

The angle

which is double of it's complement and half of it's ssupplement is equal to 60°

#Bye

Answer 2

Hello Mate... ❤

$\huge{ \bold{ \underline{ \underline{ \mathscr{ \green{ \: Answer :}}}}}}$

=> The Angle is Double if it's complement and half of its supplement angle will be 60°.

$\huge{ \bold{ \underline{ \underline{ \mathscr{ \pink{ \: thanks}}}}}}$