Question

Find the angle which is one third of the complimentary

Answer 1

Given:-

Angle A is 1/3rd of the complementary

We already know that complementary of angles is always 90°.

Then, <A is 1/3rd of 90°

(1/3)×90°

=> 30°

<A is 30°

<A + <B = 90°

30° + <B = 90°

<B = 90° - 30°

<B = 60°

Answer 2

Answer:

22.5°

Step-by-step explanation:

Let the angle be x

and its compliment be 90-x .

$= > x = \frac{1}{3} (90 - x) \\ x = (\frac{90 - x}{3} ) \\ 3 = 90 - 3 \\ 3x + x = 90 \\ 4x = 90 \\ x = \frac{90}{4} \\ x = 22.5$

Hence , the required angle is 22.5°

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