find the angle whose complement is one third of its suppliment
Answers
Answered by
13
Hii....
Let the angle be x.
Then,
Its complement= (90-x)°
Its supplement=(180-x)°
A/q,
(90-x) = 1/3 (180-x)
=) 90-x = 60 - x/3
=) 90 - 60 = -x/3 + x
=) 30 = (-x+3x)/3
=) 30 = 2x/3
=) 30×3 = 2x
=) 90 = 2x
=) x = 90/2
Hence, x = 45°
Therefore, the angle is 45°
Hope it helps u
:)
:)
Let the angle be x.
Then,
Its complement= (90-x)°
Its supplement=(180-x)°
A/q,
(90-x) = 1/3 (180-x)
=) 90-x = 60 - x/3
=) 90 - 60 = -x/3 + x
=) 30 = (-x+3x)/3
=) 30 = 2x/3
=) 30×3 = 2x
=) 90 = 2x
=) x = 90/2
Hence, x = 45°
Therefore, the angle is 45°
Hope it helps u
:)
:)
Answered by
5
the answer is 45 ° and I think I could tell you earlier
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