find the angles mark by a & b
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Answered by
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Hey mate here's your answer :)
We know that sum of all angles on a straight line is measure to 180'.
A/Q
40'+ a = 180
A = 180-40
= 140 ans
We know that a exterior angle is equal to opposite two interior angle
Therefore,
65 + b = 140
B = 140 - 65
= 75 ans
The values are
A= 140'
B= 75 '
Hope it helps you
We know that sum of all angles on a straight line is measure to 180'.
A/Q
40'+ a = 180
A = 180-40
= 140 ans
We know that a exterior angle is equal to opposite two interior angle
Therefore,
65 + b = 140
B = 140 - 65
= 75 ans
The values are
A= 140'
B= 75 '
Hope it helps you
Uvesh1234:
KYa kr rhi ho
Answered by
0
Answer:
Step-by-step explanation:Given: SP║RQ, ∠R = 90° and ∠Q = 130°.
To find: The measure of ∠P.
Answer:
It is given that SP║RQ. So let us assume that PQ is the transversal.
Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)
∠P + 130° = 180°
∠P = 180° - 130°
∠P = 50°
Now letes mark by a & b
us assume that SR is the transversal.
Therefore, ∠S + ∠R = 180° (Co - interior Angleangles mark by a & b
s are Supplementary)
∠S + 90° = 180°
∠S = 180° - 90°
∠S = 90°
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