If sin(a+b) =1 and tan(a-b)=1/root 3. Find the value of tanA+cotB
Answers
Answered by
35
sin(a+b)=1
sin(a+b)= sin 90 degree
(a+b) = 90 ..........1 eq
tan(a-b)= 1root 3
tan(a-b)= tan30
( a- b) = 30.........2 eq
by elimination
a + b=90
a - b=30
we get 2a=120
a= 60
put in 1eq
60 + b=90
b. = 90-30
b. =60
HEY MATE@!!! HOPE IT WILL HELP U
sin(a+b)= sin 90 degree
(a+b) = 90 ..........1 eq
tan(a-b)= 1root 3
tan(a-b)= tan30
( a- b) = 30.........2 eq
by elimination
a + b=90
a - b=30
we get 2a=120
a= 60
put in 1eq
60 + b=90
b. = 90-30
b. =60
HEY MATE@!!! HOPE IT WILL HELP U
aashi2203:
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Answered by
2
Answer:
Given: SP║RQ, ∠R = 90° and ∠Q = 130°.
To find: The measure of ∠P.
Answer:
It is given that SP║RQ. So let us assume that PQ is the transversal.
Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)
∠P + 130° = 180°
∠P = 180° - 130°
∠P = 50°
Now let us assume that SR is the transversal.
Therefore, ∠S + ∠R = 180° (Co - interior Angles are Supplementary)
∠S + 90° = 180°
∠S = 180° - 90°
∠S = 90°
Step-by-step explanation:
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