Question

find the angles of a triangle which are in the ratio 3:4:5.

Answer 1

let the common multiple be x,
then the angles are
3x, 4x, 5x

3x+4x+5x = 180 --(angle sum property of triangle)

12x = 180
x = 180/12
x = 15


The required angles are;
3x = 45°
4x = 60°
5x = 75°

Answer 2

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$Heya \\</p><p>The \: sum \: of \: all \: angles \: of \: a \: triangle \: is \: 180° \\ </p><p>According \: to \: the \: question \\ </p><p>Let \: the \: angles \: be \: 3x, 4x \: and \: 5x \\ </p><p>=> 3x + 4x + 5x = 180° \\ </p><p>=> 12x = 180° \\ </p><p>=> x = 15° \\ </p><p>3x = 3×15 = 45° \\ </p><p>4x = 4×15 = 60° \\ </p><p>5x = 5×15 = 75° \\</p><p>Hope \: this \: helps \: u \\ </p><p>Follow \: me \\ </p><p>Plz \: mark \: my \: ans \: as \: brainliest$

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