Question

Find the angles of a triangle whose sides are given by
x+2y = 8,3x+y=1 and x -
3y+7= 0​

Answer 1

Answer:

-16

Step-by-step explanation:

x+2y=8

2y=8-x

y=4-x

3x+y=1

3x+4-x=1

2x=1-4

2x=-3

x=-3/2

3x+y=1

3(-3/2)+y=1

-9/2+y=1

y=9/2

x-3y+7=0

-3/2-3(9/2)+7=0

-3/2-27/2+14/2=0

-3-27+14=0

-16