Find the angles of cyclic quadrilateral ABCD.Angle A=4y+20,B=3y-5,C=-4x,angleD=-7x+5.
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angle A= 4(25)+20=120 degree
angle B= 3(25)-5=70
angle C= -7(-15)+5=110
angle D= -4(-15)=60
hope it helps.
please mark it as brainliest.
angle A= 4(25)+20=120 degree
angle B= 3(25)-5=70
angle C= -7(-15)+5=110
angle D= -4(-15)=60
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