Find the angles which is double its supplement.
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Let, the supplement be x°.
and angle be 2x°.
According to the question,
x°+2x°=90°
=> 3x° =90°
=> x° =90°/3
=30°
Hence, Supplement=>x°= 30° and angle=2x° =>2×30°=60°
and angle be 2x°.
According to the question,
x°+2x°=90°
=> 3x° =90°
=> x° =90°/3
=30°
Hence, Supplement=>x°= 30° and angle=2x° =>2×30°=60°
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