Math, asked by yeshwitha2936, 7 months ago

find the answer for this question​

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Answered by mahi735
0

Answer:

Step-by-step explanation:

BY THE PROPERTY OF LOGARITHMS WE CAN WRITE,

2^log5 x = x^log5 x

NOW COME IN THE QUESTION,

3x^log5 2 - x^log5 2 = 64

Let x^log5 2 = y.

3y-y = 64

2y = 64

y = 32.

Put the value of y.

x^log5 2 = 32

2^log5 x = 2⁵

log5 x = 5

x= 5⁵

PLEASE THANK MY ANSWERS .

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