Math, asked by Aditya3211, 1 year ago

find the answer of th following.

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Answered by HarishAS
2
Hi friend, Harish here.

Here is your answer:

We Know that:

( a³ - b³ ) =  (a - b) (a² + ab + b²).

Let, a = 37 &  b = 28.

Then,

 \frac{37^{3} - 28^{3}}{[37^{2}+(37\times 28)+28^{2}]}=  \frac{a^{3} + b^{3}}{(a^{2}+ab+b^{2})}

⇒  \frac{a^{3} + b^{3}}{(a^{2}+ab+b^{2})}  =  \frac{(a-b)(a^{2}+ab+b^{2})}{a^{2}+ab+b^{2}}

Now we can cancel  a² + ab + b².

Then,

⇒  \frac{(a-b)(a^{2}+ab+b^{2})}{a^{2}+ab+b^{2}}  = ( a- b)

Now substitute a & b values,

Then,

( a - b ) = ( 37 - 28 ) =9.

Therefore 9 is the answer.
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Hope my answer is helpful to you.
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