Question

find the answer of this question ​

Answer 1

Solution :

Let us divide the field into several parts , we will find the area of each seperately .

Area of Quadrilateral ABDE :

=> Area of ∆ AFB + Area of BFD + Area of ADE

Area of ∆ AFB

> ½ × AF × BF

> ½ × 60 × 60

> 30 × 60

> 1800 m² .

Area of ∆ BFD :

> ½ × BF × DF

> ½ × 60 × 50

> 30 × 50

> 1500 m² .

Area of ∆ GDE :

> ½ × AD × GE

> ½ × [ 60 + 10 + 10 + 40 ] × 40

> 20 × 120

> 2400 m² .

Total area of figure :

> 1800 m² + 1500 m² + 2400 m²

> 5700 m².

This is the required answer.

_______________________________________________

Answer 2

Answer:

Required Answer :-

Area of the Quadrilateral

= Area of ∆ ABF + Area of BFD + Area of ADE

Now,

Area of ∆ ABF = ½ × AF × BF

$\sf \: Area \: of \bold{ \triangle }\: ABF = \dfrac{1}{2} \times 60 \times 60$

$\sf \: Area \: of \: \triangle \: ABF = \dfrac{1}{ \cancel2} \times \cancel{ 3600}$

$\sf \pink{Area \: of \: \triangle \: ABF = 1800 \: {m}^{2} }$

Now,

Area of BFD = ½ × BF × DF

$\sf \: Area \: of \: BFD = \dfrac{1}{2} \times 50 \times 60$

$\sf Area \: of \: BFD = \dfrac{1}{ \cancel2} \times \cancel{3000}$

$\sf \pink{Area \: of \: BFD = 1500 \: m {}^{2} }$

Area of GDE = ½ × AD × GE

$\sf \: Area \: of \: GDE = \dfrac{1}{2} \times \bigg \lgroup \: 60 + 10 + 10 + 40 \bigg \rgroup \times 40$

$\sf \: Area \: of \: GDE = \dfrac{1}{2} \times 120 \times 40$

$\sf \: Area \: of \: GDE = \dfrac{1}{2} \times 4800$

$\sf \pink{ Area \: of \: GDE = 2400 \: {m}^{2} }$

Total area = 1800 + 1500 + 2400

Total area = 3300 + 2400

Total area = 5700 m²