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Answers
Given:
15.90 kJ and 18.58kJ are the heats absorbed when one mole of KCl is dissolved in 20 moles of water and 200 moles of water respectively.
To find:
The heat of dilution of KCl is
Solution:
From given, we have,
15.90 kJ and 18.58kJ are the heats absorbed when one mole of KCl is dissolved in 20 moles of water and 200 moles of water respectively.
The enthalpy of hydration or dilution is changed in enthalpy when a solution containing 1 mole of solute is diluted from one concentration of the other.
So the change in enthalpy when a solution has one mole of a solute is dissolved from one concentration to another is dilution.
The change in enthalpy of hydration or dilution is given as:
Δh = Δh2 – Δh1
= 18.58 – 15.90
= -2.68 kJ
The heat of dilution of KCl is -2.68 kJ
Option (A) -2.68 kJ is correct.