Question

find the answer of this question

Answer 1

Square of 121 is 14641.
So, Sum of the digits
= 1+4+6+4+1 = 16

And the square root of 16 is 4.

Hence, the answer (1) 4 is absolutely correct.

Answer 2

according to your question
at first the square of 121
${121}^{2} = 14641$
sum of the digits of 14641 = 16
again now
find the square root of 16
$\sqrt{16 } = \sqrt{( {4}^{2} )} = {( {4}^{2}) }^{ \frac{1}{2} }$
$\sqrt{16} = {(4)}^{2 \times \frac{1}{2} }$
$\sqrt{16} = {4}^{1}$
hence answer is 4
:)