Question

find the AP whose sum of nth term is 2n^2+2​

Answer 1

Sum of n terms = 2n² + 2

S1 = Sum of the series with one term = 2(1)² + 2 = 4

S2 = Sum of the series with two terms = 2(2)² + 2 = 10

S3 = Sum of the series with three terms = 2(3)² + 2 = 20

T1 = S2 - S1 = 10 - 4 = 6

T2 = S3 - S2 = 20 - 10 = 10

Common difference = t2 - t1 = 10 - 6 = 4

A.P. = 6, (6 + 4), (6 + 8), (6 + 12)....

Answer 2

Answer:

difference....T²-T²..10-6....4

A.p...(6+4.) (6+8.) (6+12.).

Step-by-step explanation:

(n)..1. (n)..2 (n)..3.

s1= 2(1)²+2..4

s2= 2(2)²+2..8

s3= 2(3)²+2..20

T¹...s²-s¹..8-4...4..4

T²...s³-s²...20-8..16