Question

Find the apparent weight of a man weighing 49 kg on hrs when he standing in a live which is first sizing with an acceleration of 1.2 m per second square second going down with the same acceleration third falling freely under the action of gravity force going up or down with uniform velocity given ji was 9.8 metre per second square

Answer 1

Motion in a lift :

a) When lift is going up

F = m(g + a)

Doing the substitution we have :

F = 49 (9.8 + 1.2) = 49 × 11 = 539N

b) Lift going down

F = m(g - a)

Doing the substitution

F = 49 (9.8 - 1.2)

F = 49 × 8.6 = 421.4 N

3) A body experiencing free fall

F = mg

Doing the substitution we have.

F = 49 × 9.8 = 480.2 N

Answer 2

Answer:

Please mark me as a brainliest