Question

Find the appro percentage increase in area of cirlce if radious increased by 2%

Answer 1

Hii frnd...

Area of circle = $\pi r^{2}$
After increasing the radius by 2%
New radius = $\frac{51r}{50}$

Percentage increase in area = [tex] \frac{New area-Old area}{ \pi r^{2} }*100% [/tex]
=> $\pi ( (\frac{51r}{50}) - \pi r^{2}) / \pi r^{2}$*100%
=> Take $\pi r^{2}$ common
=> $( \pi r^{2}( \frac{51}{50}-1)) / \pi r^{2}$*100%
=> $\pi r^{2}\ gone\ by \ \pi r^{2}$
=> $\frac{1}{50}*100%$
=> 2%

Here is your answer...

Hope it helped u!!!