Question

Find the approximate value of √0.037 using differential approximate? ​

Answer 1

Take y=x

Let x=0.04  and Δx=−0.003,

Then, Δy=x+Δx−x

Δy=0.037−0.04

0.037=Δy+0.2

Now, dy is approximately equal to $$Δy$$ and is given by

dy=(dxdy)Δx

=2x1(−0.003)

=20.041(−0.003)

=−0.0075

Thus, the approximate value of 0.037 is 0.2−0.0075=0.1925

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Answer 2

Answer:

0.1925 is your correct answer