Find the approximate value of f(5.001)=x^3 -7x^2+15
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To find approximate value of f(5.001) we consuder x as 5
Given f ( x) = x^3 -7x^2+15
f(5.001)=f(5)=5³-7(5²)+15
=125-175+15
=140-175
=-35
the approximate value of f(5.001)≈-35
Given f ( x) = x^3 -7x^2+15
f(5.001)=f(5)=5³-7(5²)+15
=125-175+15
=140-175
=-35
the approximate value of f(5.001)≈-35
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