Question

Find the are of the triangle whose sides are in the ratio of 3:4:5 and the perimeter is 120m​

Answer 1

Answer:- 600m^2


Solution is in this picture




I hope it will help you!!!!! ✌️✌️


Plzzz mark as brainliest answer

Answer 2

$\bf \huge {\underline {\underline \red{QuEsTiOn}}}$

⠀⠀⠀⠀⠀

Find the area of the triangle whose sides are in the ratio of 3:4:5 and the perimeter is 120m.

⠀⠀⠀⠀⠀

$\bf \huge {\underline {\underline \red{AnSwEr}}}$

⠀⠀⠀⠀⠀

Given

⠀⠀⠀⠀⠀

• Perimeter of triangle = 120m.

⠀⠀⠀⠀⠀

• Ratio of sides = 3 : 4 : 5

⠀⠀⠀⠀⠀

To Find

⠀⠀⠀⠀⠀

• Area of Triangle

⠀⠀⠀⠀⠀

Solution

⠀⠀⠀⠀⠀

Let the sides be 3x, 4x and 5x.

⠀⠀⠀⠀⠀

$\bf \implies3x + 4x + 5x = 120$

⠀⠀⠀⠀⠀

$\bf \implies12x = 120$

⠀⠀⠀⠀⠀

$\bf \implies x = 120 \div 12$

⠀⠀⠀⠀⠀

$\bf \implies x = 10$

⠀⠀⠀⠀⠀

Therefore, sides are :-

⠀⠀⠀⠀⠀

3x = 3 × 10 = 30m

4x = 4 × 10 = 40m

5x = 5 × 10 = 50m

⠀⠀⠀⠀⠀

a = 30m, b = 40m and c = 50m

⠀⠀⠀⠀⠀

$\bf s = \frac{a + b + c}{2}$

⠀⠀⠀⠀⠀

$\bf = \frac{30 + 40 + 50}{2}$

⠀⠀⠀⠀⠀

$\bf = \frac{120}{2}$

⠀⠀⠀⠀⠀

$\bf = 60$

⠀⠀⠀⠀⠀

Area of Triangle by Heron's Formula

⠀⠀⠀⠀⠀

$\bf \pink { = \sqrt{s(s - a)(s - b)(s - c)} }$

⠀⠀⠀⠀⠀

$\bf = \sqrt{ 60(60 - 30)(60 - 40)(60 - 50)}$

⠀⠀⠀⠀⠀

$\bf = \sqrt{60 \times 30 \times 20 \times 10}$

⠀⠀⠀⠀⠀

$\bf = \sqrt{360000}$

⠀⠀⠀⠀⠀

$\bf = 600$

⠀⠀⠀⠀⠀

Hence, Area of triangle = 600m^2.