Question

Find the are of triangle,two sides of which are 8 cm and 11 cm and the perimeter is 32 cm

Answer 1

Answer:

Let the sides of a,b and c.

a = 8 cm

b = 11 cm

P = 32 cm

a+b+c = 32 cm

8+11+c = 32

c = 32-19

c = 13 cm

s = P/2 = 32/2 = 16 cm

s-a = 16-8 = 8 cm

s-b = 16-11 = 5 cm

s-c = 16-13 = 3 cm

Area of ∆ = √s(s-a)(s-b)(s-c)

= √16×8×5×3

= 8√2×5×3

= 8√30 cm²